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Determine Average Count by Day of Week - response (2) by ulrich

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you need to count the number of days per weekday separatly and join this to your result set. Something like: select d.AREA_NM_TURF, d.DayofWeek, casT(d.CountbyDayofWeek as decimal(15,3)) / w.num_of_days as AVG_COUNT from ( select CASE day_of _week WHEN 1 THEN 'Sun' WHEN 2 THEN 'Mon' WHEN 3 THEN 'Tue' WHEN 4 THEN 'Wed' WHEN 5 THEN 'Thu' WHEN 6 THEN 'Fri' WHEN 7 THEN 'Sat' END as DayofWeek, count(*) as num_of_days from sys_calendar.calendar where calendar_date Between '2012-08-01' AND '2012-08-30' group by 1 ) w join ( SELECT AREA_NM_TURF, Count (*) as CountbyDayofWeek, CASE ((CMTMT_DT - Date '1900-01-01') Mod 7) + 1 WHEN 7 THEN 'Sun' WHEN 1 THEN 'Mon' WHEN 2 THEN 'Tue' WHEN 3 THEN 'Wed' WHEN 4 THEN 'Thu' WHEN 5 THEN 'Fri' WHEN 6 THEN 'Sat' END as DayofWeek FROM VCTD485 Where (ASKME_CREAT_DT) Between '2012-08-01' AND '2012-08-30' AND CMTMT_DT = ASKME_CREAT_DT And Area_NM_TURF like 'AL%PCA' Group by AREA_NM_Turf, DAyofWeek ) as d on d.DayofWeek = w.DayofWeek order by d.AREA_NM_TURF, d.DayofWeek    

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